## Suppose the initial number of our Pythagorean Triple was an even number.

Let's choose 4 as our first number and use the equations from the last page.

x , (x ² - 1) ÷ 2 , (x ² + 1) ÷ 2

Our triple would become 4, 7.5, and 8.5. However this isn't a legitimate triple since Pythagorean Triples are always integer numbers.

But, if we double this "triple", we will get a legitimate triple = 8, 15, 17. Cool. And does it check out?

Does 8 ² + 15 ² = 17 ²

64 + 225 = 289 ? Yep, it works.